Simultaneous Equations with Exponents

Algebra Level 1

Given that a 3 b 2 c = 8 a^{3}b^{2}c = 8 and b c 2 = 1 bc^{2} = 1 .

What is the value of a b c abc ?


The answer is 2.

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2 solutions

Ron Lauterbach
Sep 17, 2017

You are given the terms a 3 b 2 c a^{3}b^{2}c and b c 2 bc^2 . If you multiply these variables together like shown below, you receive the expression ( a 3 b 3 c 3 a^{3}b^{3}c^{3} ), which will be equal to the value of the product of the variables you multiplied together ( 1 × 8 1 \times 8 ). a 3 b 2 + 1 c 1 + 2 = 8 × 1 = 8 a^{3}b^{2+1}c^{1+2}=8 \times 1=8 You now have: a 3 b 3 c 3 = 8 a^{3}b^{3}c^{3}=8 Take the cube root of a 3 b 3 c 3 = 8 a^{3}b^{3}c^{3}=8 to receive a b c = 2 abc=2 . The answer is 2 \boxed{2} .

can you please simplify that clearly?

Mohammad Khaza - 3 years, 8 months ago

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I added a more detailed explanation.

Ron Lauterbach - 3 years, 8 months ago

a 3 b 2 c = 8 a^3b^2c=8 ( 1 ) \color{#D61F06}(1)

b c 2 = 1 bc^2=1 ( 2 ) \color{#D61F06}(2)

Multiply ( 1 ) \color{#D61F06}(1) and ( 2 ) \color{#D61F06}(2) , we get

a 3 b 3 c 3 = 8 a^3b^3c^3=8

Extracting the cube root of both sides, we get

a b c = abc= 2 \large{\color{plum}\boxed{2}}

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