x + y y + x = 1 1 = 7
Let n be the number of real pairs ( x , y ) to the above system of equations. Define these solution pairs as ( x 1 , y 1 ) , … , ( x n , y n ) . Let
S = i = 1 ∑ n ( x i + y i ) .
Find n + S .
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Sketch or graph the two equations. You'll see they intersect only at one point. Some exploration will show that the point is (9, 4). Hence the answer is 1+9+4=14.
[P.S. Also note that
x
≤
1
1
and
y
≤
7
which greatly decreases the checking work you have to do.]
Put x=sec^2z and y=tan^2z and solve the equations. You will get only one solution satisfying the given equations i.e. x=9 and y=4. Hence the answer is 1+9+4 = 14
I don't understand how the substitution is justified. In effect you're assuming that x=y+1. Could you please explain?
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