n → ∞ lim n number of sines sin ( sin ( sin ( ⋯ ( sin ( x ) ) ) ⋯ )
Compute the limit above, where x is any real number .
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Yep. You can see that it does approach to y=0.
If the limit exists, call it L. Then the problem is when is L = sin (L). That is only true at y = 0.
You need to prove that the limit exists first.
It is given for any real number i put x=0.
This is not a solution/proof.
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It is just a value of x which satisfy the given equation and is rational.
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f ( x ) = sin x ∈ [ − 1 , 1 ] f ( x ) = sin ( sin x ) ∈ [ sin ( − 1 ) , sin ( 1 ) ] f ( x ) = sin ( sin ( sin x ) ) ∈ [ sin ( sin ( − 1 ) ) , sin ( sin ( 1 ) ) ]
As you can see,the Range of the function is deceasing , when the n → ∞ lim , Range ( R ) → 0 , Look at this graph for better understanding.