Sine here, please

Geometry Level 3

Let ABC be a triangle with side AB being 46 inches long, side BC being 58 inches long, and angle ABC being 150 degrees.

What is the area of triangle ABC in square inches?


The answer is 667.

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2 solutions

Tri Nguyen
Dec 16, 2017

Denton Young
Apr 18, 2017

By the sine rule, we know that the area, A A , is equal to 1 / 2 × A B × B C × s i n ( A B C ) 1/2 \times AB \times BC \times sin(ABC)

s i n ( 150 ) sin(150) = 0.5 0.5

1 / 2 × 46 × 58 × 0.5 = 667 1/2 \times 46 \times 58 \times 0.5 = 667

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