Sine Synesthesia

Geometry Level 4

For all positive values of sin ( 2 x ) \sin(2x) , evaluate the value of cot ( x ) cot ( 2 x ) \cot(x) \cot(2x) that maximizes sin ( x ) + cos ( 2 x ) \sin(x) + \cos(2x) .


The answer is 7.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

The expression we want to maximize can also be written, by substituting t = sin ( x ) t = \sin(x) , as 2 t 2 + t + 1 -2t^2+t+1 . Analyzing the vertex of this parabola, we see that the expression holds its maximum value for t = sin ( x ) = 1 4 t = \sin(x) = \frac{1}{4} . Because sin ( 2 x ) = 2 sin ( x ) cos ( x ) \sin(2x) = 2 \sin(x) \cos(x) , we have that cos ( x ) \cos(x) is positive, which leads to cos ( x ) = 15 4 \cos(x) = \frac{\sqrt{15}}{4} and cot ( x ) = 15 \cot(x) = \sqrt{15} . By the double cotangent formula, cot ( 2 x ) = 7 15 \cot(2x) = \frac{7}{\sqrt{15}} and thus our answer is 7. \boxed{7.}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...