If (x = y), (a=b), (c=2ay), (az = 5) and (y=3z), find the value of c.
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Among the given equations, we have y=3z. This is the substituted into c=2ay, we can get c=2a (3z) [y=3z]
Given that az=5, we substitute az in the equation c=6az, which we take from the earlier equation. So, we get:
c=2a (3z)
c=6az
c=6 (5) [az=5]
c=30