Sistema #4
Algebra
Level
1
If (x = 135), (y = 153), (z = 315), (2 + a + x - 3 + y + c + 2 + b + z + 1 = h), (a = 351), (b = 513), and (c = 531), what is the value of h ?
1996
2002
2000
1998
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1 solution
I looked at the units digit.
2+1+5-3+3+1+2+3+5+1=20, so h must end with 0, and the only choice is 2000.