Sisters = Manzu +Bizaya

We have 13 distinct numbers and distinct non-zero digits are 9 ie; $\small{\left\{1,2,3,\cdots ,8,9\right\}}= 9$ . Hence, no solution exist

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Let's prove it

Proof:

Suppose on the contrary there exist unique solution for all letters then notice that $10 < I+M = I < 18$ isnot possible unless it has carry $1$ from $Z+A$ as $I\neq M$ then $I+M >10 = 10+I \implies M=10$ which is absurd as $0< M<10$ .If $I+M <10$ then $I+M\neq I ; I+M+1 = 10 +I \Rightarrow M =9$ .

Which further follows as $B+1 = S$ and also we have $Z+A = S \implies 1 = Z+A -B$ . It's vivid that $Z+A,B$ are co-prime integers. Moreover, we must say they are consecutive integers. Now recall that $I+M$ has a carry 1 from $Z+A$ implies $Z+A>10\implies Z+A-B >1$ which contradicts $Z+A-B =1$ which proves that there exist no solution .