Situation of chaos ? #1

Algebra Level 2

$\huge \color{#3D99F6}{2^{3^{2^{3^{2^{0^{2^3}}}}}}}=\color{#20A900}{{{2^3}^{\left( 2^3 \right)}}^{2^{0^{2^3}}}}$

Which of the options is true about the above equation ?

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True Ambiguous False

1 solution

Feathery Studio
May 28, 2015

Because there is a $0$ involved on the L.H.S. and R.H.S., all exponents after it can become $0$ , and the $2$ before the $0$ will become $1$ . Now, on the L.H.S., we have an exponent of $1$ , which keeps the $3$ intact, and we have $2^{3^{8}} = 2^{6561}$ . On the R.H.S, we have an exponent of $(2^{3}) = 8$ . So our final expression is $2^{3^{8}} = 2^{6561}$ . L.H.S. $=$ R.H.S.

Situation of chaos ? #1

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1 solution

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