Sketch it

Geometry Level 4

Drawn from the origin are two mutually perpendicular straight lines forming an isosceles triangle with the straight line 2 x + y = a 2x+y=a . Then the area of triangle is a 2 η \frac{a^{2}}{\eta} . Find tan 2 ( 60 η ) \tan^{2}(60\eta) .


The answer is 3.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

The triangle is a 45-90-45 triangle. The distance of the line from (0,0) is 5 \sqrt5 . So this is the altitude from the 90 degree vertex. So area is a 2 / 5 a^2/5 . Therefore T a n 2 ( 60 5 ) = 3 Tan^2(60*5)=3 assuming the angle is in degrees. That only is possible . ........... Sorry for making a report because of my misunderstanding.

@Shivam Jadhav For clarity , please add to the problem statement that the angle 60 η 60\eta is in degrees..

Ankit Kumar Jain - 3 years, 6 months ago

Log in to reply

Yes , indeed but I think the fact that on the answer pad there wasn't written to write 3 significant digits gave me hint

Hitesh Yadav - 9 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...