It's easy that if you want to slice a circular pizza into 2 halves (of the same exact size).
However, suppose you want to slice a segment of a circular pizza such that the segment is only 1/3 of the area of the pizza. Roughly how big is the crust, with respect to the circumference to the pizza?
Choose the closest answer.
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Let r be the radius of the pizza and θ be the the central angle that subtends the segment.
Then the area of 3 1 of the pizza is A = 3 1 π r 2 and the area of the circular segment is A = 2 1 r 2 ( θ − sin θ ) .
Setting these equal to each other and solving numerically gives θ ≈ 2 . 6 0 5 (radians), which is approximately 2 π 2 . 6 0 5 ≈ 4 0 % of the circle (the same ratio as the length of the crust to the circumference of the pizza).
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Area of a segment of a circle = 2 r 2 ( θ − sin θ ) , where θ is the angle subtended by it at the centre.
Therefore, 2 r 2 ( θ − sin θ ) = 3 π r 2
θ − sin θ = 3 2 π
The solution of the above equation is at θ ≈ 2 . 6 0 5
Hence, percentage of crust in the piece = 2 π θ × 1 0 0 ≈ 4 0