Slightly harder Alphabet
Algebra
Level
2
2a+b+c+d+e = 1
a+2b+c+d+e = 2
a+b+2c+d+e = 3
a+b+c+2d+e = 4
a+b+c+d+2e = 5
find 2(a+b+c+d+e)
The answer is 5.
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1 solution
adding it all
6(a+b+c+d+e) = 15
2(a+b+c+d+e) = 5