True or False?
There exists a real matrix such that for all and .
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First consider an 8 × 8 Hadamard matrix H , that is, a matrix whose entries are all 1 or -1, with their column vectors being pairwise orthogonal (their dot product is 0). Now H T H = 8 I 8 , by construction, so that ( det H ) 2 = 8 8 = 2 2 4 and det H = ± 2 1 2 = ± 4 0 9 6 . Multiplying a row by − 1 if necessary, we can assume that det H = 4 0 9 6 . Now det ( a H ) = 4 0 9 6 a 8 = 2 0 1 8 for some a with 0 < a < 1 , and A = a H is a matrix of the required form. The claim is T r u e .