Small Leaf, Big Problem

We can see that the area of the leaf will be: $\text{ar(sqraure)} - \text{ar(remaining brown paper)}$ . And;

$\text{ar(remaining brown paper)} = 2\times (\text{ar(sqraure)} - \text{ar(quadrant)}\\=2\times\left(14^2-\dfrac{\pi 14^2}4\right)\\=2\times(196-154)=84\text{ units}^2$

Therefore, $\text{ar(leaf)} = 196-84=\boxed{112}\text{ units}^2$

From the picture above we can conclude that,

$\frac{1}{4}$ Circle Area - Triangle Area $=$ $\frac{1}{2}$ Leaf Area

$(\frac{1}{4} \times \frac{22}{7} \times 14^2) - (\frac{14 \times 14}{2}) =$ $\frac{1}{2}$ Leaf Area

$154 - 98 = \frac{1}{2}$ Leaf Area

$56 = \frac{1}{2}$ Leaf Area

$112 =$ Leaf Area

The area of the green leaf = 2(the area of the sector - the area of the triangle) = 2((phi/4) . 14.14 - 14.14/2) = 112