Smallest 3 digit number

The smallest three digit number which leaves reminders 8 and 12 when divided by 28 and 32 respectively is.......

222 204 102 202

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1 solution

Kenny O.
Aug 12, 2017

The answer can be expressed as 28y+8=32x+12
28y=32x+4
7y=8x+1
y=(8x+1)/7
8x+1 is divisible by 7 where y is an integer. The smallest possible x is x=6
32x+12= 32(6)+12= 192+12= 204

how did you get y=(8y +1)?

In the earlier line its mentioned the 7y = 8'x'+ 1...

Ojasee Duble - 3 years, 10 months ago

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