Find the sum of the roots of the monic quadratic that satisfies f ( 0 ) = 3 0 and f ( 2 ) = 0 .
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Let the quadratic equation be a x 2 + b x + c = 0 f ( 0 ) = 3 0 ⟹ Constant term of the quadratic equation is 30 . Also, f ( 2 ) = 0 ⟹ x − 2 is the factor of the equation. Now, in order for 30 to be the constant the other factor must be x − 1 5 making the equation ( x − 2 ) ( x − 1 5 ) = x 2 − 1 7 x + 3 0 , ∴ sum of roots is equal to 1 7
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Let's start with the monic quadratic in the form: x 2 + b x + c = 0 . Here, they say if x = 0 , then the quadratic equation equal 30.
0 2 + 0 + c = 3 0 ⇒ c = 3 0 .
It is also stated that inputting 2 as x will make the quadratic equation equal 0. In other words:
2 2 + 2 b + 3 0 = 0 ⇒ 4 + 2 b = − 3 0
⇒ b = − 1 7
From this, we can rewrite the equation as: x 2 − 1 7 x + 3 0 = 0
By Vieta's formula, the sum of the roots will be
− a b = − 1 − 1 7 = 1 7