SMO Past year questions

What is the largest multiple of 55 using the digits 0, 1, 2, 3, 4, 5, 6 without repetition?


The answer is 6431205.

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2 solutions

Tijmen Veltman
Jun 24, 2015

Call this number N N . We need N N to divide 5 5 , therefore the last digit must equal 0 0 or 5 5 . Furthermore, we need N N to divide 11 11 , which means that the sum of the odd digits and the sum of the even digits must be equal mod 11 11 .

The total sum of the digits is of course 0 + 1 + 2 + 3 + 4 + 5 + 6 = 21 0+1+2+3+4+5+6=21 : an odd number, therefore the 'odd sum' (call it O O ) and 'even sum' (call it E E ) cannot be precisely equal. The only remaining possibility is that they differ by 11 11 , meaning one is equal to 5 5 and the other to 16 16 . O O is the sum of 4 4 different digits, meaning O 6 O\geq 6 . Therefore O = 16 O=16 and E = 5 E=5 .

To make N N as large as possible, we can take its first digit to be 6 6 . The second digit cannot be equal to 5 5 , seeing as it is one of three odd digits that sum to 5 5 . We can take it to be 4 4 , forcing the other odd digits to be 1 1 and 0 0 . Therefore the last digit must be equal to 5 5 . Arranging the other digits from high to low (to make N N as large as possible), we obtain N = 6431205 N=\boxed{6431205} .

Tasha Kim
Jun 24, 2015

Hope this helps.

Tasha Kim - 5 years, 11 months ago

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