In an arithmetic progression if term is equals to while the term is equals to , with . Find the term.
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Let:
a m = a 1 + ( m − 1 ) δ = n (i)
a n = a 1 + ( n − 1 ) δ = m (ii)
Subtracting (i) from (ii) produces: − δ ( m − n ) = m − n ⇒ δ = − 1 . Substituting this common-difference value into either (i) or (ii) yields a 1 = m + n − 1 . These two combined values finally give the p-th term as: a p = a 1 + ( p − 1 ) δ = ( m + n − 1 ) + ( p − 1 ) ( − 1 ) = m + n − p .