A number theory problem by Áron Bán-Szabó

Is it possibe, that n 2 + n + 1 n^2+n+1 is a perfect square, where n n is a positive integer?

Yes, it's possible. No, it's not possible.

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1 solution

Áron Bán-Szabó
Aug 19, 2017

Note that n 2 n^2 and ( n + 1 ) 2 (n+1)^2 are two consecutive perfect squares. That means there's no perfect square bigger than n 2 n^2 , but lower than ( n + 1 ) 2 (n+1)^2 . However n 2 < n 2 + n + 1 < ( n + 1 ) 2 = n 2 + 2 n + 1 n^2 \ < \ n^2+n+1 \ < \ (n+1)^2=n^2+2n+1

Therefore it is not possible.

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