Two non-intersecting circles in the plane
Γ
1
and
Γ
2
are drawn centered at points
O
1
and
O
2
respectively. A circle
Γ
3
intersects
Γ
1
at points
X
1
,
X
2
and
Γ
2
at points
Y
1
,
Y
2
.
Another circle
Γ
4
intersects
Γ
1
at points
X
3
,
X
4
and
Γ
2
at points
Y
3
,
Y
4
.
Suppose lines
X
1
X
2
and
Y
1
Y
2
intersect at
K
1
and
X
3
X
4
and
Y
3
Y
4
intersect at
K
2
.
Find
∠
K
1
O
2
O
1
+
∠
O
2
K
1
K
2
in degrees.
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done it the same way sreejato! :)
easy but nice . answer is 90
Care to be a little more elaborate?
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Note that X 1 X 2 is the radical axis of Γ 1 and Γ 3 and Y 1 Y 2 is the radical axis of Γ 2 and Γ 3 . Their point of intersection, K 1 , therefore is the radical center of Γ 1 , Γ 2 , Γ 3 , which implies K 1 lies on the radical axis of Γ 1 and Γ 2 . Similarly K 2 also lies on the radical axis of Γ 1 and Γ 2 . It follows that K 1 K 2 ⊥ O 1 O 2 , and ∠ K O 2 O 1 + ∠ O 2 K 1 K 2 = 1 8 0 ∘ − 9 0 ∘ = 9 0 ∘ .