J = ∫ n + 1 e n + 2 e x ∏ i = 1 n i times ln ( ln ( ln ⋯ ( ln x ) ) ⋯ ) d x
Let A B denote the tetration function, A B = A times B B B ⋅ ⋅ ⋅ B .
Find ⌊ J + 2 ⌋ .
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Great solution +1
Cant believe its level 4
It is greatest integer of j not j!
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L i ( x ) = i times ln ( ln ( ln ⋯ ( ln x ) ) )
J = ∫ n + 1 e n + 2 e x L 1 ( x ) L 2 ( x ) … L n ( x ) 1 d x
L n ( x ) = t
x L 1 ( x ) L 2 ( x ) … L n − 1 ( x ) 1 d x = d t
∴ J = ∫ e e e t d t = [ ln ( t ) ] e e e = e − 1
⌊ J + 2 ⌋ = ⌊ e − 1 + 2 ⌋ = ⌊ e + 1 ⌋
2 < e < 3
3 < e + 1 < 4
J = ⌊ e + 1 ⌋ = 3