Find the smallest positive integer which when multiplied by 7 gives an integer whose decimal representation is entirely nines.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Not sure if this is coincidence but the answer is also correspondent to the point at which the decimal for one seventh repeats itself eg. 0.142857
Log in to reply
It's not coincidence.
9 9 9 9 9 9 / 7 = 1 0 0 0 0 0 0 × 1 / 7 − 1 × 1 / 7 = 1 4 2 8 5 7 . 1 4 2 8 5 7 − . 1 4 2 8 5 7 = 1 4 2 8 5 7 .
For each digit, we need to find the formula, ( 7 D + P ) % 1 0 = 9 , with D being the single-digit integer we are looking for and P being the digit already in the Place we are trying to turn into a 9 . Remember % means modulus.
For the 1 's place, the formula is ( 7 D + 0 ) % 1 0 = 9 . D is 7 because ( 7 × 7 + 0 ) % 1 0 = ( 4 9 + 0 ) % 10 = 49 \% \(10 = 9
For the 1 0 's place, the formula is ( 7 D + 4 ) % 1 0 = 9 . D is 5 because ( 7 × 5 + 4 ) % 1 0 = ( 3 5 + 4 ) % 10 = 39 \% \(10 = 9
For the 1 0 0 's place, the formula is ( 7 D + 3 ) % 1 0 = 9 . D is 8 because ( 7 × 8 + 3 ) % 1 0 = ( 5 6 + 3 ) % 10 = 59 \% \(10 = 9
For the 1 , 0 0 0 's place, the formula is ( 7 D + 5 ) % 1 0 = 9 . D is 2 because ( 7 × 2 + 5 ) % 1 0 = ( 1 4 + 5 ) % 10 = 19 \% \(10 = 9
For the 1 0 , 0 0 0 's place, the formula is ( 7 D + 1 ) % 1 0 = 9 . D is 4 because ( 7 × 2 + 1 ) % 1 0 = ( 2 8 + 1 ) % 10 = 29 \% \(10 = 9
For the 1 0 0 , 0 0 0 's place, the formula is ( 7 D + 2 ) % 1 0 = 9 . D is 1 because ( 7 × 1 + 2 ) % 1 0 = ( 7 + 2 ) % 10 = 9 \% \(10 = 9
Thus, the smallest integer is 1 4 2 , 8 5 7 .
Problem Loading...
Note Loading...
Set Loading...
Divide the no. which entirely consist nine's.
AS,THE ANSWER SHOULD BE IN INTEGERS+. THEREFORE,ANSWER WILL BE 142857.