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A 30 ohms resistance coil is used to melt of ice in 35 seconds . If there are no heat losses and the latent heat of fusion of ice is . The current drawn by the coil is?
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1 solution
If it takes 336 /g of energy to melt 1 g of ice, then it took 336*50 or 16800 J to melt 5 g of ice in 35 seconds. Hence, it took 16800/35 J/s or 480 watts to melt 5 g of ice. 48 watts/ 30 Ohms= 16 Amp^2. or 4 Amp.