So, who's it gonna be?

Calculus Level 3

Naruto and Madara are having an epic duel.

Naruto fires his signature move, the Rasenshuriken whose initial size is 100 m 3 100~m^3 and is growing uniformly at the rate of 20 m 3 / sec 20~m^3/\textrm{sec} .

At the same moment, Madara, being a guy who can absorb Chakra uses his absorption ninjutsu to disperse the Rasenshuriken. Assume that he can disperse it at a uniform rate of 25 m 3 / sec 25~m^3/\textrm{sec} and that Naruto forms the Rasenshuriken in 20 sec 20\textrm{ sec} and once it is formed, it cannot be dispersed in any way and will surely hit Madara.

So, what will happen? Will Madara or Naruto succeed?

Madara manages the disperse the jutsu in 10-15 seconds. Naruto is gonna Rasenshuriken him! :D Madara manages to disperse the jutsu at the last moment. Not enough info to determine the answer.

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6 solutions

Discussions for this problem are now closed

Patrick Engelmann
Mar 17, 2015

Solution 1 :

The size of the rasenshuriken at time t t can be be expressed as s ( t ) = 100 m 3 + 20 m 3 s t s(t) = 100 m^{3} + 20 \frac{ m^{3}}{s} \cdot t .

The amount of size that has been absorbed by Madara at time t t can be expressed as a ( t ) = 25 m 3 s t a(t) = 25 \frac{ m^{3}}{s} \cdot t

The point in time when Madara absorbed the complete rasenshuriken will be when s ( t ) = a ( t ) s(t) = a(t) . Let's call this point t 1 t_{1} . Then

100 m 3 + 20 m 3 s t 1 = 25 m 3 s t 1 100 m^{3} + 20 \frac{ m^{3}}{s} \cdot t_{1} = 25 \frac{ m^{3}}{s} \cdot t_{1}

100 m 3 = 5 m 3 s t 1 100 m^{3} = 5 \frac{ m^{3}}{s} \cdot t_{1}

t 1 = 20 s t_{1} = \boxed{20s}

Hence, Madara will make it in the last moment.

Solution 2 :

Watch the anime or read the manga

Upvoted for solution 2. :D

Prasun Biswas - 6 years, 2 months ago
Brock Brown
Mar 17, 2015

Action simulation, go!

Python 2.7:

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rasenshuriken = 100
growth_rate = 20
absorb_rate = 25
seconds = 20
for second in xrange(seconds):
    rasenshuriken += growth_rate
    rasenshuriken -= absorb_rate
    if rasenshuriken <= 0:
        if second >= 10 and second <= 15:
            print "Madara manages to disperse the jutsu in 10-15 seconds."
        break
if rasenshuriken == 0:
    print "The rasenshuriken is dispersed at the last moment!"
elif rasenshuriken > 0:
    print "Naruto is so gonna rasenshuriken him."
else:
    print "Madara overcomes Naruto."

Scott Spaniol
Mar 16, 2015

The difference in dispersion is 5 m^3/s so you divide the initial amount by 5 and it takes 20 s to disperse the original 100 m^3. Hence at the last moment if it took less time for formation then there would not be enough Tim to disperse the original amount.

A more formal approach would be to solve the following first order differential solution:

d V d t = ( 5 ) \frac{\textrm{d}V}{\textrm{d}t}=(-5)

The solution would be: V = ( 100 5 t ) m 3 V=(100-5t)~m^3 where t t is in seconds. Plugging t = 20 t=20 gives V = 0 V=0 implying the answer.

Prasun Biswas - 6 years, 3 months ago
Bhupendra Jangir
Mar 23, 2015

The rate of dispersion is greater than growing by 5 m^3/sec.Thus the Rasenshuriken whose initial size is 100 m^3,will be disperse in the time 100/5=20 sec. by Madara.

Rishikesh Roshan
Mar 18, 2015

In 1st sec. The size is 95 cubic meter in 2nd sec.size is 90 cubic meter 3rd sec. 85 cubic meter Hence. Using AP a=95, d=-5, n th term=0.... if we solve using : nth term=a+(n-1)d... We get n=20.... Hence in the last moment Madra manges to disperse jutsu....

Vikram Venkat
Mar 16, 2015

Since the rate of dipersion is greater than the rate of formation, Madara wins obviously. But since the difference in rates are low, he manages it at the last second. Logic

Is that so? What about when the time is reduced from 20 sec 20\textrm{ sec} to 10 sec 10\textrm{ sec} ? Does the same logic hold?

Prasun Biswas - 6 years, 3 months ago

No the same logic does not hold if time is decreased from 20 to 10 seconds ,

Sangeet Bhatia - 6 years, 2 months ago

Yes, I know that! I was asking him to imply that his solution is wrong.

Prasun Biswas - 6 years, 2 months ago

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