Naruto and Madara are having an epic duel.
Naruto fires his signature move, the Rasenshuriken whose initial size is 1 0 0 m 3 and is growing uniformly at the rate of 2 0 m 3 / sec .
At the same moment, Madara, being a guy who can absorb Chakra uses his absorption ninjutsu to disperse the Rasenshuriken. Assume that he can disperse it at a uniform rate of 2 5 m 3 / sec and that Naruto forms the Rasenshuriken in 2 0 sec and once it is formed, it cannot be dispersed in any way and will surely hit Madara.
So, what will happen? Will Madara or Naruto succeed?
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Upvoted for solution 2. :D
Action simulation, go!
Python 2.7:
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The difference in dispersion is 5 m^3/s so you divide the initial amount by 5 and it takes 20 s to disperse the original 100 m^3. Hence at the last moment if it took less time for formation then there would not be enough Tim to disperse the original amount.
A more formal approach would be to solve the following first order differential solution:
d t d V = ( − 5 )
The solution would be: V = ( 1 0 0 − 5 t ) m 3 where t is in seconds. Plugging t = 2 0 gives V = 0 implying the answer.
The rate of dispersion is greater than growing by 5 m^3/sec.Thus the Rasenshuriken whose initial size is 100 m^3,will be disperse in the time 100/5=20 sec. by Madara.
In 1st sec. The size is 95 cubic meter in 2nd sec.size is 90 cubic meter 3rd sec. 85 cubic meter Hence. Using AP a=95, d=-5, n th term=0.... if we solve using : nth term=a+(n-1)d... We get n=20.... Hence in the last moment Madra manges to disperse jutsu....
Since the rate of dipersion is greater than the rate of formation, Madara wins obviously. But since the difference in rates are low, he manages it at the last second. Logic
Is that so? What about when the time is reduced from 2 0 sec to 1 0 sec ? Does the same logic hold?
No the same logic does not hold if time is decreased from 20 to 10 seconds ,
Yes, I know that! I was asking him to imply that his solution is wrong.
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Solution 1 :
The size of the rasenshuriken at time t can be be expressed as s ( t ) = 1 0 0 m 3 + 2 0 s m 3 ⋅ t .
The amount of size that has been absorbed by Madara at time t can be expressed as a ( t ) = 2 5 s m 3 ⋅ t
The point in time when Madara absorbed the complete rasenshuriken will be when s ( t ) = a ( t ) . Let's call this point t 1 . Then
1 0 0 m 3 + 2 0 s m 3 ⋅ t 1 = 2 5 s m 3 ⋅ t 1
1 0 0 m 3 = 5 s m 3 ⋅ t 1
t 1 = 2 0 s
Hence, Madara will make it in the last moment.
Solution 2 :
Watch the anime or read the manga