Socks in drawer

Suppose some blue socks and the same number of red socks are in a drawer. Suppose it turns out that the minimum number of socks I must pick in order to be sure of getting at least one pair of the same color is the same as the minimum number I must pick in order to be sure of getting at least two socks of different colors. How many socks are in the drawer?

2 10 4 1 12 8 6

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1 solution

Let's suppose there are n n socks.

the minimum number of socks I must pick in order to be sure of getting at least one pair of the same color is 3 3 .

the minimum number I must pick in order to be sure of getting at least two socks of different colors is n 2 + 1 \frac{n}{2} +1 . Therefore, 3 = n 2 + 1 n = 4 3 = \frac{n}{2} +1 \Rightarrow n = 4 since the minimum number of socks I must pick in order to be sure of getting at least one pair of the same color is the same as the minimum number I must pick in order to be sure of getting at least two socks of different colors.

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