Solar Cooker, Anyone?

Geometry Level 4

Jimmy wants to build a parabolic solar cooker for his culinary project. It is 6 meters in diameter and the distance between the bottom of his solar cooker to the edge of the cooker is 5 meters.

At what height from the bottom of the bowl should he put his food in order to maximize the cooking temperature?

If the height, in meters, is expressible in the form a b \dfrac{a}{b} , where a a and b b are coprime positive integers, find a + b a+b .


The answer is 25.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Let y 2 = 2 p x {{y}^{2}}=2px , A B AB , A D AD and F F be the equation , the diameter, the axis of symmetry and the focus of the of the parabola respectively.
Then O A = 5 OA=5 is the distance between the bottom, O O , of the solar cooker to the edge of the cooker.

By Pythagorean theorem on the right-angled O A D \triangle OAD , O D = 4 OD=4 , hence the point A A has coordinates ( 4 , 3 ) \left( 4,3 \right) . These coordinates satisfy the equation of the parabola, thus 3 2 = 2 p × 4 p = 9 8 {{3}^{2}}=2p\times 4\Rightarrow p=\dfrac{9}{8} . The point where the cooking temperature is maximum is the focus of the parabola, whose coordinates are ( p 2 , 0 ) ( 9 16 , 0 ) \left( \dfrac{p}{2},\ 0 \right)\equiv \left( \dfrac{9}{16},\ 0 \right) , hence, the required height from the bottom of the bowl is 9 16 \dfrac{9}{16} .

For the answer, a + b = 25 a+b=\boxed{25} .

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...