Solution, Solute and Solvent Problem 3

Chemistry Level 1

At 1 0 ∘ C 10^\circ \text{C} , 50 g 50\text{ g} of water can dissolve 10.45 g 10.45\text{ g} of K N O X 3 \ce{KNO_3} and become saturated. Determine the solubility of K N O X 3 \ce{KNO_3} at 1 0 ∘ C 10^\circ \text{C} .

You may refer Chemistry - Solution, Solute and Solvent Note.
20.9 g 20.9\text{ g} 20.9 g K N O X 3 20.9\text{ g } \ce{KNO_3} 20.9 g of water 20.9\text{ g of water} 20.9 g / 100 g 20.9\text{ g}/100\text{ g}

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Christopher Boo by Christopher Boo , 24, Singapore

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2 solutions

Anish Puthuraya
Jan 22, 2014

Solubility = = The maximum amount of K N O 3 KNO_3 that can be dissolved in a specific amount of water.

Hence,
By definition,
Solubility = 10.45 g / 50 g = 10.45g/50g water

As this is a ratio,
Solubility is also = 20.9 g / 100 g = \boxed{20.9g/100g}

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Shantanu Lankr
May 13, 2014

If 10.45g KNO3 can form a saturated solution with water when dissolved in 50g of water, 20.9g of KNO3 would form a saturated solution with water when dissolved in 100g of water.

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