Solution to Inequality
If the solution to the inequality is what is the value of
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1 solution
Let us examine two cases for this inequality:
CASE I: x 2 − 8 x − 8 < 8 x − 8 ⇒ x 2 − 1 6 x < 0 ⇒ x ( x − 1 6 ) < 0 ⇒ x ∈ ( 0 , 1 6 ) .
CASE II: x 2 − 8 x − 8 < − 8 x + 8 ⇒ x 2 − 1 6 < 0 ⇒ ( x + 4 ) ( x − 4 ) < 0 ⇒ x ∈ ( − 4 , 4 ) .
Thus, the inequality is valid for x ∈ ( − 4 , 1 6 ) ⇒ 1 6 − 4 = 1 2 .