Solve

here,7(6/14) = 3 , and we got ( 1^(1/3)+((2^3)^(1/3))= 1+2 = 3

First, you need to know that a ^ (1/2) = $\sqrt{a}$

Similarly, a ^ (1/3) = cube root a

So,

according to the question,

 cube root { (7 * 6 / 14) - 2 } + cube root { (7 * 6 / 14) + 5}

= cube root { (6 / 2) - 2 } + cube root { (6 / 2) + 5}

= cube root { 3 - 2 } + cube root { 3 + 5}

= cube root { 1 } + cube root { 8 }

= 1 + 2

= 3

The solution is quite complex because I don't know the symbol of cube root on brilliant. So note that cube root { a } means a is under the root of order 3. Hope you understand.

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