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Probability Level 2

Person A can solve 80% of question paper and person B can solve 60%. The probability that at least one of them will solve a problem from that question paper selected at random is:

0.70 0.88 0.48 0.92

Deepak Gowda by Deepak Gowda , 32, India

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3 solutions

Fahad Shaikh
Jun 4, 2014

Probabiltiy of missing the question paper for A = 0.2,

Probability of missing the question paper for B = 0.4

combined missing probablity = 0.2 x 0.4 = 0.08

Combined Solving probability = 1 - 0.08 = 0.92

3 Helpful 0 Interesting 1 Brilliant 0 Confused

I did it the same way :)

Shreya R - 6 years, 5 months ago
Prajin Sp
Jul 30, 2014

P ( A ∪ B ) = P ( A ) + P ( B ) − P ( A ∩ B ) = 0.8 + 0.6 − 0.8 × 0.6 = 0.92 P\left( A\cup B \right) =P\left( A \right) +P\left( B \right) -P\left( A\cap B \right) =0.8+0.6-0.8\times 0.6=\boxed { 0.92 }

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Deepak Gowda
Jun 4, 2014

Probability of A solving the question paper P(A)=4/5

Probability of A not solving the question paper P( A' )=1/5

Probability of B solving the question paper P(B)=3/5

Probability of B not solving the question paper P( B' )=2/5

Probability of at least one solving a problem

P = P(A) P( B' ) + P(B) P( A' ) + P(A)* P(B)

P = 23/25 = 0.92

1 Helpful 0 Interesting 0 Brilliant 0 Confused

P = P(A)P( B' ) + P(B)P( A' ) + P(A)* P(B) can you explain this ?

Archit Sharma - 6 years, 11 months ago

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