Solve for X 2

First step is to square both sides of the equation to get rid of the square root sign.

$(\sqrt{2x+5y})^2=6^2$

$2x+5y=36$

Since we are solving for $x$ , subtract $5y$ from both sides of the equation.

$2x+5y-5y=36-5y$

$2x=36-5y$

Now, to isolate $x$ in the left side, we must divide both side of the equation by $2$ .

$\dfrac{2x}{2}=\dfrac{36-5y}{2}$

$\boxed{x=\dfrac{36-5y}{2}}$

Isolating $x$ gives: $\begin{aligned} \sqrt{2x+5y}&=6 \\ 2x+5y&=36 \\ 2x&=36-5y \\ x&=\boxed{\frac{36-5y}{2}} \end{aligned}$ Therefore, the answer is $\displaystyle \frac{36-5y}{2}$ .

Here are the steps to solve this equation for $x$ .

$\sqrt{2x + 5y} = 6$

$\sqrt{2x + 5y}^2 = 6^2$

$2x + 5y = 36$

$2x + 5y - 5y = 36 - 5y$

$2x = 36 - 5y$

$\frac{2x}{2} = \frac{36 - 5y}{2}$

$x = \frac{36 - 5y}{2}$