Mixing It Up

Algebra Level 4

There are two containers A and B filled with mentha oil with different prices and with volumes 140 and 60 liters respectively. Equal quantities are drawn from both A and B in such a manner that the oil drawn from A is poured in into B and oil drawn from B is poured into A. After doing so, the price per liter becomes equal in both containers. What is the (equal) quantity that was drawn?

Image credit: Wikipedia AlfvanBeem


The answer is 42.

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3 solutions

Joshua Daniel
Jun 27, 2014

First we must create an equation that will make use of all the information available to us. Assuming the cost of the different mentha oils to be y and x, and the amount of oil drawn from both containers to be k we get the equation :

                 (140y+kx-ky)/140 = (60x-kx+ky)/60

from here on it is a simple matter of rearranging the terms until we arrive at a form where we can directly compare the coefficient of one term to the coefficient of the opposing term.

so

   420(y-x) = 10k(y-x)

   10k=420

    k=42
Dipanjan Pal
Aug 12, 2014

(140 * 3+60 * 7)/2*(7+3)=42

Deepak Gowda
Jun 26, 2014

Since equal oil quantities were drawn from containers,

oil drawn was, x = (140 - 60) / 2 = 40

i dont get this. Let's say A price was 1 Rs/ltr and B price was 2 Rs/ltr. Then after taking 40 ltr from each, price of A per ltr will be (100 1+40 2)/140 =9/7 and for B it will be (20 2+40 1)/60 = 8/6.

Correct answer should be 42 by which we will get A=(98 1+42 2)/140=13/10 per ltr B=(18 2+42 1)/60=13/10 per ltr

Nitin sINGAL - 6 years, 11 months ago

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Thanks. I have updated the answer to 42.

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Calvin Lin Staff - 6 years, 11 months ago

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