Do You Know Your Log Properties?

Algebra Level 1

log 7 35 + log 7 35 log 7 25 = ? \large \log_7 35 + \log_7 35 - \log_7 25 = \ ?


The answer is 2.

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5 solutions

Using the Properties of Logarithms , we can rewrite log 7 35 + log 7 35 log 7 25 \log _{7}35+\log _{7}35-\log _{7}25

as

log 7 [ 7 × 5 ] + log 7 [ 7 × 5 ] log 7 [ 5 × 5 ] \log_{7}[7\times5]+\log_{7}[7\times5]-\log_{7}[5\times5]

log 7 7 + log 7 5 + log 7 7 + log 7 5 [ log 7 5 + log 7 5 ] \Rightarrow \log_{7}7+\log_{7}5+\log_{7}7+\log_{7}5-[\log_{7}5+\log_{7}5]

log 7 7 + log 7 7 \Rightarrow \log_{7}7 + \log_{7}7

2 \Rightarrow \boxed{2}

Manish Dash
Apr 20, 2015

i too did in d same way

Sai Sameera Bunni - 5 years, 10 months ago

log 7 35 + log 7 35 log 7 25 = log 7 35 × 35 25 = log 7 7 2 = 2 \log_{7}35 + \log_{7}35 - \log_{7}25 = \log_{7}\dfrac{35 \times 35}{25} = \log_{7}7^2 = \boxed{2}

Gustavo Milla
Jul 30, 2015

Fajar Maulana
Mar 12, 2016

^7log((35)^2/25) = ^7log49 = 2

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