Solve it if you can

Algebra Level 1

if a=90, b=90

solve this:

a 2 a^{2} x 39 - b 2 b^{2} x 29


The answer is 81000.

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3 solutions

Munem Shahriar
Jun 29, 2017

Given that ,

a = 90 a = 90

b = 90 b = 90

Now,

( a ) 2 × 39 ( b ) 2 × 39 (a)^2 \times 39 - (b)^2 \times 39

9 0 2 = 8100 90^2 = 8100

So, 8100 × 39 = 315900 8100 \times 39 = 315900

8100 × 29 = 234900 \Rightarrow 8100 \times 29 = 234900

Now subtract the both,

\Rightarrow ( 315900 234900 ) = 81000 (315900 - 234900) = 81000

We have, 39 a 2 29 b 2 29 a 2 + 10 a 2 29 b 2 29 ( a b ) ( a + b ) + 10 a 2 39a^2 - 29b^2 \Rightarrow 29a^2+10a^2 - 29b^2 \Rightarrow 29(a-b)(a+b) + 10a^2 Now a = b = 90 a=b=90 so a b = 0 a - b =0 ,Therefore we just have to find the value of 10 a 2 10a^2 which is 81000 \boxed{81000}

Atharv Toraskar
Sep 26, 2015

90^2 = 8100 not 81000 so you are wrong

Mohammad Farhat - 2 years, 9 months ago

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