Solve the system

Algebra Level 1

Solve the system of equations

{ x 3 y = 25 4 x + 5 y = 19 \large {\begin{cases} x-3y=-25 \\ 4x+5y=19 \end{cases}} Give your answer as x + y x+y .


The answer is 3.

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5 solutions

Mohammad Khaza
Nov 2, 2017

given that,

x 3 y = 25 x-3y=-25 ..........(1)

4 x + 5 y = 19 4x+5y=19 .........(2)

now, doing [(1) . 4] and then [(2)-(1)] we get, \text{[(1) . 4] and then [(2)-(1)] we get,}

4 x + 5 y = 19 4x+5y=19

4 x 12 y = 100 4x-12y=100

o r , 17 y = 119 o r,17y=119

o r , y = 7 o r, y=7

so, putting the value of y=7 in equation (1) we get, x = 4 x=-4

s o , x + y = 4 + 7 = 3 s o, x+y=-4+7=3

Lew Sterling Jr
May 28, 2019

[ x 3 y = 25 4 x + 5 y = 19 ] x 3 y = 25 x 3 y + 3 y = 25 + 3 y x = 25 + 3 y 4 x + 5 y = 19 4 ( 25 + 3 y ) + 5 y = 19 100 + 12 y + 5 y = 19 100 + 17 y = 19 100 + 17 y + 100 = 19 + 100 17 y = 119 17 y 17 = 119 17 y = 7 x = 25 + 3 y x = 25 + 3 ( 7 ) x = 25 + 21 x = 4 x + y = 4 + 7 = 3 \begin{matrix} \begin{bmatrix}x-3y=-25\\ 4x+5y=19\end{bmatrix}\\\\ x-3y=-25\\ x-3y+3y=-25+3y\\ x=-25+3y\\\\ 4x+5y=19\\ 4\left(-25+3y\right)+5y=19\\ -100+12y+5y=19\\ -100+17y=19\\ -100+17y+100=19+100\\ 17y=119\\ \frac{17y}{17}=\frac{119}{17}\\ y=7\\\\ x=-25+3y\\ x=-25+3(7)\\ x=-25+21\\ x=-4\\\\ x+y\\ =-4+7\\ =\mathbf{3} \end{matrix}

Munem Shahriar
Nov 2, 2017

x 3 y = 25.... ( 1 ) x-3y=-25 ....(1)

4 x + 5 y = 19...... ( 2 ) 4x+5y=19......(2)

After multiplying the first equation by 5 and the second equation by 3, we get

5 x 15 y = 125 5x-15y = -125

12 x + 15 y = 57 12x + 15y = 57

Now, adding the two equations

5 x + 12 x = 125 + 57 5x+12x = -125+57

17 x = 68 \Rightarrow 17x = -68

x = 4 \Rightarrow x = -4

Substituting x = 4 x = -4 in equation ( 2 ) (2)

4 ( 4 ) + 5 y = 19. 4(-4)+5y=19.

16 + 5 y = 19 \Rightarrow -16+5y=19

5 y = 35 \Rightarrow 5y = 35

y = 7 \Rightarrow y = 7

Hence x + y = 4 + 7 = 3 x + y = -4 + 7 = \boxed{3}

André Hucek
Nov 2, 2017

{ x 3 y = 25 4 x + 5 y = 19 {\begin{cases} x-3y=-25 \\ 4x+5y=19 \end{cases}}

Let ( x 3 y = 25 ) (x-3y=-25) be line 1 ) 1) and ( 4 x + 5 y = 19 ) (4x+5y=19) be line 2 ) 2)

1 ) x 3 y = 25 x = 3 y 25 2 ) 4 ( 3 y 25 ) + 5 y = 19 = 17 y = 119 = y = 7 1) \ x-3y=-25 \implies x = 3y - 25 \\ 2) \ 4 \cdot (3y-25) +5y = 19 \\ = 17y = 119 \\ = y = \color{#D61F06}7

Plugging in y = 7 y=7

2 ) 4 x + 5 7 = 19 = 4 x = 19 35 = x = 4 2) \ 4x + 5 \cdot 7 = 19 \\ = 4x = 19-35 \\ = x = \color{#3D99F6}-4

x \color{#3D99F6}x + + y \color{#D61F06}y = = 4 \color{#3D99F6}-4 + + 7 \color{#D61F06}7 = 3 = \boxed{3}

Relevant wiki: System of Linear Equations (Simultaneous Equations)

x 3 y = 25 x-3y=-25 \Longleftrightarrow 1 \color{#D61F06}\boxed{1}

4 x + 5 y = 19 4x+5y=19 \Longleftrightarrow 2 \color{#D61F06}\boxed{2}

Solve for x x in 1 \color{#D61F06}\boxed{1} in terms of y y then substitute in 2 \color{#D61F06}\boxed{2} . We have

x = 25 + 3 y x=-25+3y

Then,

4 ( 25 + 3 y ) + 5 y = 19 4(-25+3y)+5y=19

100 + 12 y + 5 y = 19 -100+12y+5y=19

17 y = 119 17y=119

y = 7 y=7

It follows that

x = 25 + 3 ( 7 ) = 25 + 21 = 4 x=-25+3(7)=-25+21=-4

Now substitute x = 4 x=-4 and y = 7 y=7 into the two original equations. We have

x 3 y = 25 x-3y=-25

4 3 ( 7 ) = 25 -4-3(7)=-25

25 = 25 -25=-25 (The statement is true.)

4 x + 5 y = 19 4x+5y=19

4 ( 4 ) + 5 ( 7 ) = 19 4(-4)+5(7)=19

16 + 35 = 19 -16+35=19

19 = 19 19=19 (The statement is true.)

Finally, the desired answer is

4 + 7 = 3 -4+7=\boxed{3}

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