Solve the system of equations
⎩ ⎨ ⎧ x − 3 y = − 2 5 4 x + 5 y = 1 9 Give your answer as x + y .
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[ x − 3 y = − 2 5 4 x + 5 y = 1 9 ] x − 3 y = − 2 5 x − 3 y + 3 y = − 2 5 + 3 y x = − 2 5 + 3 y 4 x + 5 y = 1 9 4 ( − 2 5 + 3 y ) + 5 y = 1 9 − 1 0 0 + 1 2 y + 5 y = 1 9 − 1 0 0 + 1 7 y = 1 9 − 1 0 0 + 1 7 y + 1 0 0 = 1 9 + 1 0 0 1 7 y = 1 1 9 1 7 1 7 y = 1 7 1 1 9 y = 7 x = − 2 5 + 3 y x = − 2 5 + 3 ( 7 ) x = − 2 5 + 2 1 x = − 4 x + y = − 4 + 7 = 3
x − 3 y = − 2 5 . . . . ( 1 )
4 x + 5 y = 1 9 . . . . . . ( 2 )
After multiplying the first equation by 5 and the second equation by 3, we get
5 x − 1 5 y = − 1 2 5
1 2 x + 1 5 y = 5 7
Now, adding the two equations
5 x + 1 2 x = − 1 2 5 + 5 7
⇒ 1 7 x = − 6 8
⇒ x = − 4
Substituting x = − 4 in equation ( 2 )
4 ( − 4 ) + 5 y = 1 9 .
⇒ − 1 6 + 5 y = 1 9
⇒ 5 y = 3 5
⇒ y = 7
Hence x + y = − 4 + 7 = 3
{ x − 3 y = − 2 5 4 x + 5 y = 1 9
Let ( x − 3 y = − 2 5 ) be line 1 ) and ( 4 x + 5 y = 1 9 ) be line 2 )
1 ) x − 3 y = − 2 5 ⟹ x = 3 y − 2 5 2 ) 4 ⋅ ( 3 y − 2 5 ) + 5 y = 1 9 = 1 7 y = 1 1 9 = y = 7
Plugging in y = 7
2 ) 4 x + 5 ⋅ 7 = 1 9 = 4 x = 1 9 − 3 5 = x = − 4
x + y = − 4 + 7 = 3
Relevant wiki: System of Linear Equations (Simultaneous Equations)
x − 3 y = − 2 5 ⟺ 1
4 x + 5 y = 1 9 ⟺ 2
Solve for x in 1 in terms of y then substitute in 2 . We have
x = − 2 5 + 3 y
Then,
4 ( − 2 5 + 3 y ) + 5 y = 1 9
− 1 0 0 + 1 2 y + 5 y = 1 9
1 7 y = 1 1 9
y = 7
It follows that
x = − 2 5 + 3 ( 7 ) = − 2 5 + 2 1 = − 4
Now substitute x = − 4 and y = 7 into the two original equations. We have
x − 3 y = − 2 5
− 4 − 3 ( 7 ) = − 2 5
− 2 5 = − 2 5 (The statement is true.)
4 x + 5 y = 1 9
4 ( − 4 ) + 5 ( 7 ) = 1 9
− 1 6 + 3 5 = 1 9
1 9 = 1 9 (The statement is true.)
Finally, the desired answer is
− 4 + 7 = 3
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given that,
x − 3 y = − 2 5 ..........(1)
4 x + 5 y = 1 9 .........(2)
now, doing [(1) . 4] and then [(2)-(1)] we get,
4 x + 5 y = 1 9
4 x − 1 2 y = 1 0 0
o r , 1 7 y = 1 1 9
o r , y = 7
so, putting the value of y=7 in equation (1) we get, x = − 4
s o , x + y = − 4 + 7 = 3