Value

Algebra Level 3

16 ( m 2 + n 2 ) 2 + 56 ( m 2 + n 2 ) ( 3 m 2 2 n 2 ) + 49 ( 3 m 2 2 n 2 ) 2 16 (m^2 + n^2)^2 + 56 (m^2 + n^2) (3 m^2 - 2 n^2) + 49 (3 m^2 - 2 n^2)^2

Evaluate the expression above for m = 6 m=6 and n = 7 n=7 .

1111111 168100 116555 160000

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1 solution

Chew-Seong Cheong
Mar 21, 2017

x = 16 ( m 2 + n 2 ) 2 + 56 ( m 2 + n 2 ) ( 3 m 2 2 n 2 ) + 49 ( 3 m 2 2 n 2 ) 2 = 4 2 ( m 2 + n 2 ) 2 + 2 4 ( m 2 + n 2 ) 7 ( 3 m 2 2 n 2 ) + 7 2 ( 3 m 2 2 n 2 ) 2 = ( 4 ( m 2 + n 2 ) + 7 ( 3 m 2 2 n 2 ) ) 2 = ( 4 m 2 + 4 n 2 + 21 m 2 14 n 2 ) 2 = ( 25 m 2 10 n 2 ) 2 = ( 900 490 ) 2 = 41 0 2 = ( 400 + 10 ) 2 = 160000 + 8000 + 100 = 168100 \begin{aligned} x & = 16\left(m^2+n^2\right)^2 + 56\left(m^2+n^2\right)\left(3m^2-2n^2\right) + 49\left(3m^2-2n^2\right)^2 \\ & = 4^2\left(m^2+n^2\right)^2 + 2\cdot 4 \left(m^2+n^2\right)\cdot 7 \left(3m^2-2n^2\right) + 7^2\left(3m^2-2n^2\right)^2 \\ & = \left(4\left(m^2+n^2\right) + 7 \left(3m^2-2n^2\right)\right)^2 \\ & = \left(4m^2+4n^2 + 21 m^2- 14n^2 \right)^2 \\ & = \left(25 m^2- 10n^2 \right)^2 \\ & = \left(900- 490 \right)^2 \\ & = 410^2 \\ & = (400+10)^2 \\ & = 160000 + 8000 + 100 \\ & = \boxed{168100} \end{aligned}

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