Solve this! 2

Geometry Level 1

sin ⁡ 3 0 ∘ × cos ⁡ 2 0 ∘ tan ⁡ 3 0 ∘ × cos ⁡ 9 0 ∘ = ? \dfrac{\sin30^\circ \times \cos20^\circ}{\tan30^\circ} \times \cos90^\circ = \, ?

-1 1/2 -8 1 43 6 1000 0

Gourab Roy by Gourab Roy , 20, India

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2 solutions

Don't solve this.

⇒ sin ⁡ 3 0 ∘ × cos ⁡ 2 0 ∘ tan ⁡ 3 0 ∘ × cos ⁡ 9 0 ∘ \Rightarrow \dfrac{\sin30^\circ \times \cos20^\circ}{\tan30^\circ} \times \cos90^\circ

sin ⁡ 3 0 ∘ × cos ⁡ 2 0 ∘ tan ⁡ 3 0 ∘ × 0 = 0 \dfrac{\sin30^\circ \times \cos20^\circ}{\tan30^\circ}×0=\boxed{0}

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Gourab Roy
Jan 16, 2016

Ans= 0; because cos 90 degrees =0

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