Solve this equation

Calculus Level pending

( 2 x 2 + 3 x + 1 ) ( 3 x + 2 ) 2 = x 4 \large (2{ x }^{ 2 }+3x+1){ (3x+2) }^{ 2 }={ x }^{ 4 }

Solve the equation above in R \mathbb R .

4 6 + 2 + 2 17 ; 4 6 2 + 2 17 \frac { 4 }{ 6+\sqrt { 2+2\sqrt { 17 } } } ;\frac { -4 }{ 6-\sqrt { 2+2\sqrt { 17 } } } 4 6 + 2 + 17 ; 4 6 2 + 17 \frac { -4 }{ 6+\sqrt { 2+\sqrt { 17 } } } ;\frac { -4 }{ 6-\sqrt { 2+\sqrt { 17 } } } 4 6 + 2 + 2 17 ; 4 6 2 + 2 17 \frac { -4 }{ 6+\sqrt { 2+2\sqrt { 17 } } } ;\frac { -4 }{ 6-\sqrt { 2+2\sqrt { 17 } } } 4 6 + 2 + 17 ; 4 6 2 + 17 \frac { 4 }{ 6+\sqrt { 2+\sqrt { 17 } } } ;\frac { -4 }{ 6-\sqrt { 2+\sqrt { 17 } } }

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