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Algebra Level 2

If x + 1 x = 99 x+ \frac {1}{x} = 99 , find the value of 100 x 3 x 2 + 103 x + 3 \frac {100x}{3x^2 + 103x + 3}


The answer is 0.25.

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Raushan Sharma by Raushan Sharma , 20, India

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1 solution

Raushan Sharma
Feb 8, 2015

Given, x + 1 x = 99 x + \frac{1}{x} = 99 , So we get x 2 + 1 = 99 x x^2 + 1 = 99x , multiplying 3 on both sides, 3 x 2 + 3 = 297 x 3x^2 + 3 = 297x . So, putting 3 x 2 + 3 3x^2 + 3 as 297 x 297x in the question we get the answer as 100 x 400 x \frac{100x}{400x} , i.e. 1 4 = 0.25 \frac{1}{4} = 0.25

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Please edit your question as x + 1 x = 99 x+ \frac {1}{x} = 99 & 100 x 3 x 2 + 103 x + 3 \frac {100x}{3x^2 + 103x + 3} . It is a bit easy to read.

Purushottam Abhisheikh - 6 years, 4 months ago

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Thanx I did it. I edited my question. Actually I didn't know all the codes to be used properly

Raushan Sharma - 6 years, 4 months ago

Good ,

x + 1 x = 99 x + \dfrac{1}{x} = 99

100 x 3 x 2 + 103 x + 3 \frac {100x}{3x^2 + 103x + 3}

= 100 3 x + 3 x + 103 = \dfrac{100}{ 3x + \dfrac{3}{x} + 103}

= 100 3 × 99 + 3 + 100 = \dfrac{100}{3\times99 + 3 + 100}

= 100 4 × 100 = \dfrac{100}{4\times100}

If you want to learn latex then there are many options - 1) Wikipedia and the toogle latex features allows you to read others latex.

U Z - 6 years, 3 months ago

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