SOLVE THIS!!!!

Algebra Level 3

a chemist has one solution containing 50 % acid and a second one containing 25% of acid how much of each should be used to make 10 litres of a 40 % acid solution ? let the quantity of 50% acid as (a) and the quantity of 25%acid as (b) then write the answer as 50 *a + 25 *b


The answer is 400.

Palash Som by Palash Som , 21, India

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1 solution

Uhm.... Can I reword this question? It seems that the answer is just part of the solution. Maybe the ratio of a to b, perhaps?

Now, to the solution.

Let x be the no. of liters of the 50% acid solution. (a)

Let 10 -x be the no. of liters of the 25% acid solution. (b)

. 5 ( x ) + . 25 ( 10 − x ) = . 4 ( 10 ) .5(x) + .25(10-x) = .4(10) 50 x + 25 ( 10 − x ) = 40 ( 10 ) 50x + 25(10 - x) = 40(10) 50 x + 25 ( 10 − x ) = 400 50x + 25(10 - x) = 400 50 a + 25 b = 400 50a + 25b = 400

There.

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