Solving Linear Equation by Guessing

Algebra Level 2

Given that f ( x ) = m x + b f(x) = mx+b such that f ( 2 ) = 0 f(2)=0 , f ( x 1 ) = f 1 f(x_1)=f_1 , and f ( x 2 ) = f 2 f(x_2)=f_2 . Find the value of f 1 x 2 f 2 x 1 f 1 f 2 . \frac{f_1x_2 - f_2x_1}{f_1-f_2}.

2 0 None of these choices 3

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Paul Ryan Longhas
Feb 19, 2015

( x 1 , f 1 ) = > f 1 = m x 1 + b (x_1,f_1) => f_1=mx_1+b ( x 2 , f 2 ) = > f 2 = m x 2 + b (x_2,f_2)=> f_2=mx_2+b ( 2 , 0 ) = > b m = 2 (2,0) => \frac{-b}{m} = 2 So, x 2 ( m x 1 + b ) x 1 ( m x 2 + b ) m x 1 + b ( m x 2 + b ) \frac{x_2(mx_1+b) - x_1(mx_2+b)}{mx_1+b - ( mx_2+b)} = > b ( x 2 x 1 ) m ( x 1 x 2 ) => \frac{b(x_2-x_1)}{m(x_1-x_2)} = > b m = 2 => \frac{-b}{m} = 2

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...