Consider the polynomial
Given that for then find .
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Let g ( k ) = f ( k ) − k . Then g ( k ) is a 4th degree polynomial with roots 1 , 2 , 3 and 4 , and so
g ( k ) = ( k − 1 ) ( k − 2 ) ( k − 3 ) ( k − 4 ) . Plugging in k = 5 gives us that
g ( 5 ) = 4 × 3 × 2 × 1 = 2 4 , and so f ( 5 ) = g ( 5 ) + 5 = 2 9 .