Some more average numbers

Number Theory Level pending

Let x 0 , x 1 , x 2 , x_0, x_1, x_2,\ldots be a sequence of a numbers satisfying the recursion,

x n = x n 1 + x n 2 2 , x_{n} =\dfrac{x_{n-1} + x_{n-2}}2 ,

where n = 2 , 3 , 4 n = 2,3,4 \ldots .

If x 0 = 0 x_0 = 0 and x 1 = 1890 x_1 = 1890 , find the following:

lim n x n \lim_{n \rightarrow \infty} x_n


The answer is 1260.

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1 solution

Geoff Pilling
Jul 30, 2016

lim n x n = 1980 × n = 0 ( 1 / 2 ) n = 1980 × 2 3 = 1260 \lim_{n\to \infty} x_n = 1980 \times \sum_{n=0}^{\infty} (-1/2)^n= 1980 \times \frac{2}{3} = \boxed{1260}

What do you mean by "The sequence is equivalent to a number"?

Great question. There is a simple way of writing out what each of these terms should be.

Calvin Lin Staff - 4 years, 10 months ago

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Yeah, I had a bit of unnecessary verbiage... There, I've removed it... :)

Geoff Pilling - 4 years, 10 months ago

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