Some Nice Dynamics

Calculus Level 5

Let x x be a function of time, such that the following are satisfied:

x ¨ + x 2 + x ˙ 3 = 0 x ( 0 ) = 0 x ˙ ( 0 ) = 0 \ddot{x} + x^2 + \dot{x} - 3 = 0 \\ x(0) = 0 \\ \dot{x}(0) = 0

What is the maximum value of x x over time?


The answer is 2.2451.

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1 solution

Mark Hennings
Jul 27, 2019

Although this is a nonlinear equation, it models a particle of mass 1 1 that is subject to a force 3 x 2 3-x^2 (which is always directed towards the value x = 3 x=\sqrt{3} ) and a further damping force x ˙ -\dot{x} . Thus it is clear that the particle will (eventually) settle down to the equilibrium position of x = 3 x = \sqrt{3} . Since we are asked for a maximum value, and not a supremum value, the first swing of the oscillation must take the particle from x = 0 x=0 to beyond x = 3 x=\sqrt{3} , and the maximum value of x x will then be obtained as the maximum value of x x during this first swing.

Numerical integration tells us that the maximum value occurs at t = 2.10373 t = 2.10373 , and is 2.24513 \boxed{2.24513} .

I used Laplace transform and I got a maximum value of 2.643.

Chiang Jun Siang - 1 year, 10 months ago

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The Laplace transform is generally used to solve linear differential equations. While there is a formula for the Laplace transform of x 2 x^2 as a type of autoconvolution of the Laplace transform of x x with itself, I am not sure how you intend to use this result. My answer (and I guess, Steven's) comes from simple numerical integration of the differential equation.

Mark Hennings - 1 year, 10 months ago

I don't think there's a simple closed form that you can get with a Laplace transform or any other symbolic method- numerics are required.

D G - 1 year, 10 months ago

Thanks for the clarification. @Mark Hennings. I misread x^2 as t^2.

Chiang Jun Siang - 1 year, 10 months ago

Here's the phase flow represented by vector field V ( x , y ) = ( y , 3 y x 2 ) V(x,y) = (y, 3 - y - x^{2}) . I think it looks pretty cool.

Here's the link if someone wants to play - Field play .

Uros Stojkovic - 1 year, 10 months ago

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That looks really cool

Krishna Karthik - 1 year, 1 month ago

Man I tried it myself and it was so amazing! GLSL really is powerful. 1000000 particles; my GPU had no problem and it looked so beautiful!

Krishna Karthik - 1 year, 1 month ago

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