Some number theory fun with the taxicab number

Let d d be the greatest integer such that for every positive integer n n , d ( n 1729 n ) . d \ \Big| \ \big(n^{1729}-n\big).

Find the number of (positive) divisors of d d .


Inspiration .


The answer is 16384.

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1 solution

Manuel Kahayon
Jun 3, 2017

Notice that if p p is a prime, and p 1 1728 p-1 | 1728 , then n 1728 1 ( m o d p ) n^{1728} \equiv 1 \pmod p , implying n 1729 n ( m o d p ) n^{1729} \equiv n \pmod p , or that n 1729 n 0 ( m o d p ) n^{1729} - n \equiv 0 \pmod p .

Note, however, that even if p 1 1728 p-1 | 1728 , then if p n p|n but p 2 n p^2 \nmid n , then n 1729 n n^{1729} - n is not divisible by p 2 p^2 .

This implies d d is squarefree.

Thus, the primes which divide d d are those for which p 1 1728 p-1 | 1728 . UtiLiZiNG wOlFraM aLpHA, we can see that the primes are 2 , 3 , 5 , 7 , 13 , 17 , 19 , 37 , 73 , 97 , 109.193 , 433 , 577 2,3,5,7,13,17,19,37,73,97,109.193,433,577 . Notice that d d is the product of these, thus since d d has 14 14 primes in its factorization, d d has 2 14 = 16384 2^{14} = \boxed{16384} positive divisors.

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