S = n = 1 ∑ ∞ 2 − n + n = 1 ∑ ∞ 3 − n + n = 1 ∑ ∞ 4 − n + n = 1 ∑ ∞ 5 − n + n = 1 ∑ ∞ 6 − n + ⋯
Does the infinite sum above converge or diverge ?
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Let S ∞ ( k ) = n = 1 ∑ ∞ ( k ) − n . It is well know that our sum up to some term n is evaluated by S − n ( k ) = 1 − k − 1 a ( 1 − k − n ) where a is the first term of the series in or case k 1 . Now taking n → ∞ lim ( S − n ( k ) ) = k k − 1 k 1 = k − 1 1 .
Therefore our sum turns into S = 1 + 2 1 + 3 1 + 4 1 + 5 1 + 6 1 + ⋯ or the Harmonic Series which Diverges .