Some simple factorization

Level 2

Let A, M and C be non- negative integers such that A+M+C=12. What is the maximum value of AMC + AM + MC + CA. Note: The numbers A, M, and C are not necessarily distinct.


The answer is 112.

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1 solution

A + M + C = 12 12 divided by three terms = 4 ( 12 / 3 = 4 ) . Thus A M C + A M + M C + C A = ( 4 4 4 ) + ( 4 4 ) + ( 4 4 ) + ( 4 4 ) = 64 + 16 + 16 + 16 = 64 + 48 = 112 Which basically means tha A=4, M=4 and C=4. A+M+C=12\\ 12 \text{ divided by three terms } = 4 (12/3 = 4). \text{ Thus } AMC+AM+MC+CA = (4*4*4)+(4*4)+(4*4)+(4*4)=64+16+16+16=64+48=112\\ \text{Which basically means tha A=4, M=4 and C=4.}

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