Someone said that 0. 9 = 1 0. \overline{9} = 1

Calculus Level 2

Statement One: Let 0.4 9 = x \text{Let} \ 0.4\overline{9} = x

Statement Two: 10 x = 4. 9 \implies 10x = 4.\overline{9}

Statement Three: 100 x = 49. 9 100x = 49.\overline{9}

Statement Four: x = 0.4 9 = 45 90 = 1 2 \implies x = 0.4\overline{9} = \cfrac{45}{90} = \cfrac{1}{2}

Since from Statement Four: , 0.4 9 = 45 90 = 1 2 0.4\overline{9} = \cfrac{45}{90} = \cfrac{1}{2} , multiplying both sides by 2,

Statement Five: [ 0.4 9 ] 2 = [ 1 2 ] 2 = 1 \implies \left[ 0.4\overline{9} \right ] \cdot 2 = \left[ \cfrac{1}{2} \right ] \cdot 2 = 1

Upon multiplying, we see that

Statement Six: [ 0.4 9 ] 2 = 0. 9 8 = 1 \left[ 0.4\overline{9} \right ] \cdot 2 = 0.\overline{9}8 = 1

Statement Seven: But upon searching, famously, 1 = 0. 9 1 = 0.\overline{9}

Statement Eight: 0. 9 8 = 0. 9 \therefore 0.\overline{9}8 = 0.\overline{9}

But, it will break the "reflexive property of equality" .

Which Statement Is The Start Of The Mistake In The Said Argument?


The answer is 6.

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1 solution

Md Zuhair
Mar 16, 2017

It is qiute clear that when we multiply 2 with 0.49 recurring.. then it will not become 0.98 recurring

I am not sure.

Also the nine recurring goes on forever so there can't really be an 8 at the end if there's no end

Austin Dong - 4 years, 2 months ago

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Yes you're correct

Md Zuhair - 4 years, 2 months ago

Yes. This is correct.

When I was younger I often used to call 0.0000000....1 as the smallest positive real number. Now I know that you can't place a digit in the end if you're stating by recurrence that there is NO END.

Tapas Mazumdar - 4 years, 2 months ago

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