⎩ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎧ x 1 7 + x 2 7 + x 3 7 + ⋯ + x n 7 = 7 x 1 8 + x 2 8 + x 3 8 + ⋯ + x n 8 = 8 x 1 9 + x 2 9 + x 3 9 + ⋯ + x n 9 = 9 x 1 1 0 + x 2 1 0 + x 3 1 0 + ⋯ + x n 1 0 = 1 0
Does there exist positive real numbers x 1 , x 2 , x 3 , … , x n with n ≥ 4 such that the system of equations above is satisfied?
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Assume there does exist positive real number solutions to the equations. Let S p = i = 0 ∑ n x i p , where p is a positive integer. By the Cauchy-Schwarz Inequality,
S d S d + 2 = ( x 1 d + x 2 d + ⋯ + x n d ) ( x 1 d + 2 + x 2 d + 2 + ⋯ + x n d + 2 ) ≥ ( x 1 2 d + 2 + x 2 2 d + 2 + ⋯ + x n 2 d + 2 ) 2 = ( x 1 d + 1 + x 2 d + 1 + ⋯ + x n d + 1 ) 2 = S d + 1 2 .
Thus, S 7 S 9 ≥ S 8 2 , and S 8 S 1 0 ≥ S 9 2 . Multiplying these together gives S 7 S 1 0 ≥ S 8 S 9 . We know that S 7 = 7 , S 8 = 8 , S 9 = 9 , S 1 0 = 1 0 . Plugging these in gives 7 ( 1 0 ) ≥ 8 ( 9 ) , which is clearly false. Thus, there are no positive real numbers x 1 , x 2 , … , x n such that the system of equations is true.
Note that we can extend the argument to prove that, for all positive integers a , b such that b ≥ a + 2 , we have S a S b ≥ S a + 1 S b − 1 .