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Geometry Level 4

Let e e be the eccentricity of the curve 0.44444 x 2 − 5.33333 x + 16 = 8 y − y 2 0.44444x^2 - 5.33333x + 16 = 8y - y^2 . Then, what is the value of 9.8 ⌊ e ⌋ 9.8\lfloor e\rfloor ?

Notation: ⌊ ⋅ ⌋ \lfloor \cdot \rfloor denotes the floor function .

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The answer is 0.00.

Aniket Verma by Aniket Verma , 24, India

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2 solutions

Aniket Verma
Mar 16, 2015

The given equation is a equation of this ellipse − -

The e c c e n t r i c i t y eccentricity of any ellipse is always < 1 <1 , hence [ e ] = 0 [e] = 0 .

so, 9.8 [ e ] = 0 9.8[e] = 0 too.

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Ashutosh Sharma
Mar 19, 2018

write 0.4444..as 4/9 and 5.333.. as 16/3 equation becomes (2/3x-4)^2+(y-4)^2=16 which is equation of ellipse and its e<1 therefore its GIF is 0 hence ans is 0

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